On a steeper slope, the jogger can run at an average speed of 5.3 miles per hour up the slope and 6.7 miles per hour going down the slope. how long, in hours, the full trip will take (1 mile uphill and 1 mile downhill). give an exact answer expressed as a fraction in simplest terms and then give a decimal approximation correct to three decimal places. (hint: use the same method as in #1.) reduced fraction: decimal approximation:

On a steeper slope, the jogger can run at an average speed of 5.3 miles per hour up the slope and 6.7 miles per hour going down the slope.

distance = rate times time.

In this problem, distance = 1 mile = rate times time

In the first case, the rate is 5.3 mph, so 1 mile= (5.3 mph)(time), and (time) = 

 1 mile
= 0.189 hour
5.3 mph

In the second case, the rate is 6.7 mph, and

 1 mile
= 0.149 hour
6.7 mph

The total transit time (up and down) is 0.189 hour plus 0.149 hour, or 

0.338 hour, or 20.3 minutes.

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.