Urgent asap answer. im stuck on this

The formula for the surface area of a regular pyramid is SA = B + 1/2Pl.

B is equal to the area of the base.  To find the area of a regular hexagon, use the formula 1/2aP.

To find the apothem, divide one side length by two to get 3. The perimeter is 6 · 6 = 36 = P

1/2 · 3 · 36 = 54 = B

Now that we found the area of the base, let's move on to the second part of the equation.  l is the slant height of one lateral face of the regular pyramid. Use the Pythagorean Theorem to find such side.

a² + b² = c²

3² + 8² = c²

9 + 64 = c²

√73 = c = l

Putting it all together...

SA = 54 + 1/2(36)(√73)

SA = 54 + 18√73

Alternatively: 207.79 approx.