Not really sure how to solve this. an expression is shown below: f(x) = −16x2 + 22x + 3 part a: what are the x-intercepts of the graph of the f(x)? show your work. part b: is the vertex of the graph of f(x) going to be a maximum or minimum? what are the coordinates of the vertex? justify your answers and show your work. part c: what are the steps you would use to graph f(x)? justify that you can use the answers obtained in part a and part b to draw the graph.

A) to find the x-intercepts, set the equation equal to zero and solve for x  -16x²+22x+3=0    -(2x-3)(8x+1)=0  by factoring**either -(2x-3)=0 or 8x+1=0if -(2x-3)=0  ⇒ solve for x  ⇒ you get x=3/2if 8x+1=0  ⇒ solve for x  ⇒ you get x=-1/8so you have 2 x-intercepts which agrees with the graph of this function. noticed that it does look like the graph is hitting the x-axis at those two x-values**if you don't remember how to factor, feel free to use the quadratic formula, completing the square, or any other method you are familiar with to solve for quadraticsb) the function is negative and a quadratic which means it is a parabola opening downward (looks like a mountain) so you will have a maximum value. the "peak" of the mountain is called the vertex (x,y). in order to find the vertex, you can use the formula  x= -b/(2a). this will give you the x-value of the vertex.  in this case, a and b are the coefficients in the original functions. a=-16 and b=22use these a and b values to find the x=coordinate of the vertex. once you find it, you can then find the y-value by plugging in the x-value that you just found onto the original formula f(x)= -16x²+22x+3your final answer for the vertex should look in the form (x,y)c) now that you have the vertex, you have an idea of what the graph looks like (mountain), and you know the points on the x-axis where that the graph is supposed to touch (part a) you are all set to sketch ithope this ! : )

Part a: to find the x intercept,substitute in 0 for y and solve for x.x-intercept: (3/2,/8,0)part b: the vertex of the graph  is going to be a minimum.vertex coordinates: (0.69)(10.56)