The volume of fuel in a tank changes at a rate given by the equation v'\left(t\right)=\frac{4t}{\sqrt[3] {t^2+3}},\: t\ge0 v ′ ( t ) = 4 t t 2 + 3 3 , t ≥ 0 at t=\sqrt{[\textbf{d}]} t = [ d ] hours the tank holds 9.[\textbf{b}] 9. [ b ] gallons. what is the volume of fuel in the tank after [\textbf{c}] [ c ] hours? round answer to one decimal place.