The general form of the equation of a circle is x2 + y2 + 42x + 38y − 47 = 0. the equation of this circle in standard form is . the center of the circle is at the point , and its radius is units. the general form of the equation of a circle that has the same radius as the above circle is .

(-21,-19)

Standard form

Step-by-step explanation:

We are given the equation of circle

General equation of circle:

Centre: (-g,-f)

Radius:

Compare the equation to find f, g and c from the equation

Centre: (-21,-19)

Radius (r)

Standard form of circle:

The centre of circle at the point (-21,-19) and its radius is .

The general form of the equation of a circle that has the same radius as the above circle is standard form.

The center of the circle is at the point (-21,-19), and its radius is   units.

The standard form of circle:

Step-by-step explanation:

The given the equation of circle :-

The general equation of circle is given by :

Here, the center of circle= (-h,-g)

and radius =

Now, Comparing the given equation to the general equation, we get  

Thus, the center of the given circle= (-21,-19)

Radius of given circle =

Now, the standard form of circle will be

b). 4320 have a nice day

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b