Sketch the graph of y=2(x+1)^2 and identify the axis of symmetry.

The axis of symmetry is (-1,0)

Hope this helps!

The axis of symmetry of this equation is at -1.

We can determine this in any equation in vertex form just by looking at it. Firstly, start with the base form of vertex form.

y = (x - h)^2 + k

In this equation (h, k) is the vertex. Working by this fact, we know the vertex is (-1, 0). The axis of symmetry is always the x value of the vertex, which allows us to state the vertex at x = -1.

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