The surface areas of two similar figures are 36 in2 and 49 in2 . if the volume of the smaller figure is 648 in3, what is the volume of the larger figure?

Area is a squared measure of the one-to-one measure of the figures. If the surface areas of the figures, from smaller to larger, are 36 and 49, by taking the square roots of those numbers, you get the perimeter measure of the figures, which is the one-to-one measure. The square root of 36 is 6, and the square root of 49 is 7. Now, in order to find the ratio of the volumes smaller to larger, we take that one-to-one measure and cube it, since volume is a cubed measure. We will set up the proportions to find the cubed measures first. My proportion will be set up with the smaller figure's info on top and the larger figure's info on bottom: . Those are the cubed ratios.  Now we will set up our equation to solve for the volume of the larger: . Now we can cross-multiply to solve for x, the volume of the larger figure. 216x = 222264. Dividing both sides by 216 gives us a volume for the larger figure of 1029 inches cubed. There you go!

i do not know the answer

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it