Asample of 100 wood and 100 graphite tennis rackets are taken from the warehouse. if 13 wood and 10 graphite are defective and one racket is randomly selected from the sample, find the probability that the racket is wood or defective.

Let's split the problem in non-intersecting subsets: we have good wood racquets, defective wood rackets, good graphite racquets, defective graphite rackets.

The probability that the racket is wood or defective covers the following subsets: good wood, defective wood and defective graphite, which have, respectively, , and elements.

Since the total is elements, the probability is

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

it is true

step-by-step explanation:

all the combinations add up i used   calculator