Abin contains 63 light bulbs of which 9 are defective. if 3 light bulbs are randomly selected from the bin with replacement, find the probability that all the bulbs selected are good ones. round to the nearest thousandth if necessary.

With replacement, probability of selecting a good bulb remains

(63-9)/63

=6/7

If the bulbs are selected WITH replacement three times, then

P(all good)

= (6/7)^3 (by the multiplication rule)

= 216/343

= 0.630 (to three decimal places)

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".