Will the brainliest ! solve for x and y. 946x+642y=911

While you cannot solve 946x+642y=911 for numerical values of x and y, you can indeed solve 946x+642y=911 first for x and then for y:

-911 - 642y

For x: 946x+642y=911 becomes 946x = 911 - 642y, or x =

946

911-946x

For y: 946x+642y=911 becomes 642y = 911-946x, or y =

642

This is one of the Diophantine equations. The solution is usually positive integers. This is an exception. It either requires fractions (I hope not) or negative numbers.

So let's see what we have.

Let's start with some obvious statements.

Is there any kind of integer that will solve this? My inclination is to say no. 911 is an odd number. How can 2 evens be manipulated to give an odd? No way using integers that I know of. So it looks like there are an infinite number of real solutions but no integers.

946x+642y=911

Is there any common factor to each of the numbers? Put another way, is 911 prime? The other two are not. 911 is prime. Our next step is to graph it. Maybe that will tell us something. We get the x and y intercepts, but nothing near an answer. You can go to desmos yourself and put this graph in. Just click on any point that looks reasonable to you. They are all give at least 1 decimals.

I think your teacher is just trying to work with awkward numbers. So work with awkward numbers. You could always just put in say 3 for x and solve for y.

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!