Bob and carl each renter the same kind of moving truck from ez move. there was a flat rental fee plus charge per mile that the truck was driven. bob cost for his truck was $112.96 for 138 miles. carl’s cost for his truck was $142.78 for 209 miles. which equation can be used to represent the cost of the rental truck

It's a linear function: y = mx + b

We have (138; 112.96); (209; 142.78)

substitute the values of x and y to the formula of slope m:

Now we have:

We must find b. Substitute the value of x and y from first pair of numbers:

y = 0.42x + 55

y = 0.42x + 55

Step-by-step explanation:

Let the equation for the cost of the truck be represented by y = mx + b,

where y = cost of truck per mile, x = number of miles, m = charge of the truck per mile and b = rental fee.

We are given that,

Cost for Bob's truck ( y ) = $112.96 for x = 138 miles, and

Cost for Carl's truck ( y ) = $142.78 for x = 209 miles.

This gives us the equations,

142.78 = 209m + b

112.96 = 138m + b

Subtracting these equations, we get,

29.82 = 71m

i.e. m = 0.42

Substituting the value of ' m ' in first equation, we get,

142.78 = 209 × 0.42 + b

i.e. 142.78 = 87.78 + b

i.e. b = 55.

Hence, the equation for the cost of the truck is y = 0.42x + 55

55

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b