Me db is a diagonal of parallelogram abcd, what is the measure of adb

The sum of the measures of the interior angles of a polygon of n sides is

180(n - 2)

A parallelogram has 4 sides, so n = 4.

The sum of the measures of the interior angles of a parallelogram (and all quadrilaterals) is

180(4 - 2) = 180 * 2 = 360

Also, opposite angles of a parallelogram are congruent.

Angles A and C are congruent, so m<A = m<C = 112

m<ADC = m<ABC since they are opposite angles.

m<ADC + m<ABC + m<A + m<C = 360

m<ADC + m<ADC + 112 + 112 = 360

2m<ADC = 136

m<ADC = 68

m<ADB + m<BDC = 68

m<ADB + 27 = 68

m<ADB = 41

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2