[will mark as brainliest] what is the inverse of the function below? f(x) = 2^x + 6 a.) f^-1(x) = 6 + log2x b.) f^-1(x) = log2(x + 6) c.) f^-1(x) = 6log2x d.) f^-1(x) = log2(x - 6)

What is the inverse of the function below?

f(x) = 2^x + 6

1) Replace "f(x)" with "y" y = 2^x + 6

2) Interchange x and y: x=2^y + 6

3) Solve this for y: 2^y = x - 6 Take the log to the base 2 of both sides:

y = (log to the base 2 of) (x-6)

4) replace y with

-1

f (x)

We obtain:

-1

f (x) = (log to the base 2 of) (x-6)

0.02040816326

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!