Law of sines: what is the approximate perimeter of the triangle? use the law of sines to find the answer. a.  4.6 unitsb. 5.7 units c. 6.9 units d. 9.2 units

Option D. 9.2 units.

Step-by-step explanation:

In the ΔJKL ⇒ ∠J + ∠K + ∠L = 180

                      ∠J + 67 + 74 = 180° ⇒ ∠J = 39°

In the given triangle JKL we apply law of sines

= =

Now we take  =

=

JL =

= 3.36 units

Now =

=

JK =

    =

    = 3.51 units

So perimeter of the triangle = 3.36 + 3.51 + 2.3 = 9.15 units ≈ 9.2 units.

Option D is the answer.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

they disappear if your absent from to long. i found out that the hard way.

step-by-step explanation:

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