What are the center and radius of the circle given by the equation ? (x-3)^2+(y+4)^2=4 a. (3, –4); 2 b. (–3, 4); 2 c. (3, –4); 4 d. (–3, 4); 4

General formula of the circle

(x-a)² + (y - b)² = r²,

where (a,b) - coordinates of the center, r - radius of the circle.

(x-3)²+(y+4)²=4

(x-3)²+(y+4)²=2²

So, the center is (3, -4) and radius r = 2.

A.(3, –4); 2

the answer is d on edge

step-by-step explanation: