Graph y = 1 - x 2 and y = e -x on the same set of coordinate axes. use the graph to find the positive solution of the equation 1 - x 2 = e -x to the nearest tenth.

It's important to use proper symbols here in presenting math problems.

y = 1 - x 2 and y = e -x

should be written as: y = 1 - x^2 and y = e^( -x), so that there is no doubt regarding which exponent you mean.

To help y ou get started:

y = 1 - x^2

has a parabolic graph with vertex/ maximum at (0,1),

and y = e^( -x) has the graph of a decaying exponential; its y-intercept is (0,1). This graph appears primarily in Quadrant I, but also in Quadrant II, but never in Q III or Q IV.

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

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step-by-step explanation: