Find the linearization l(x) of the function at a. f(x) = x4 + 4x2, a = 1

The formula of linearization is

L = f(a)+f'(a)(x-a)

We have

And it is given in the question that a=1.

So f(a) = f(1) = 1+4=5

Now we need to find f'(a) and for that , first we need to find f'(x).

At a=1,

Substituting the values of f(1) and f'(1) in the linearization formula

L=5+12(x-1)

L= 5+12x-12

L= 12x -7

And that's the required linearization .

step-by-step explanation:

this is not a question

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.