Which is the solution t other equation (x-2)(x+5)=18

(x-2)(x+5)=18

x²-2x+5x-10 =18

x² + 3x -28 = 0 -28 = 7*(-4), 3=7+(-4)

(x+7)(x-4)=0

x= - 7, x=4

(x-2)(x+5)=18

\\expand expression

x² -2x + 5x - 10 = 18

\\combine like terms

x² + 3x - 10 = 18

\\Take away 18 from both sides

x² + 3x - 28 = 0

\\factorise x² + 3x - 28

(x + 7)(x - 4) = 0

\\apply zero product property

x + 7 = 0 or x - 4 = 0

\\Evaluate

x = -7 or x = 4

x = -7 or 4

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

step-by-step explanation:

sorry i just needed points for a quiz plz for give me