Aright triangle is removed from a rectangle as shown in the figure. find the area of the remaining part of the rectangle. [area of a triangle = 1/2(b)(h)]

I found the same problem with its corresponding image.

The rectangle has a length of 8 inches and width of 6 inches.
The right triangle was taken from the width. Its short leg measures 2 inches and the remainder of the width was 2 inches.

Area of the rectangle = Length x Width
A = 8 inches * 6 inches
A = 48 square inches.

Area of a right triangle = 1/2 a h
a is the short leg = 2 inches
h is the long leg = width - remainder of the width = 6 in. - 2 in. = 4 inches.

Area = 1/2 * 2 in. * 4in.
Area = (1*2*4)/2
A = 8/2
A = 4 square inches.

Area of Rectangle - Area of Triangle = Area of remaining figure.

48 sq. in - 4 sq. in. = 44 sq. inches.

Letter b sorry i’m i’m wrong xx