Find the values of x and y that make these triangles congruent by hl.

Leg CB = x and leg DE = y - 1. Becuase of the markings on the triangles, we know that CB = DE; therefore, x = y - 1. So let's use that x value when we set the 2 hypotenuses equal to each other. Before any substition, 3x - 2 = 2y + 1. Subbing in for x we have 3(y - 1) - 2 = 2y + 1. And 3y - 3 - 2 = 2y + 1. Combining like terms we have y = 6. If y = 6, we will sub it into the leg equation to find x. x = y - 1; therefore, x = 6 - 1 and x = 5. There you go! x = 5 and y = 6

- 1.613 = -1.6 or -1.61

-1.522 = -1.5 or -1.52

0.587 = 0.6 or 0.59

3.079 = 3.1 or 3.08

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