For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. y = -2x2  + 2x +2 show the steps so i can see how you got your answer and understand it a little more. you! : ) correct answer will get branliest answer

we have that

y = -2x² + 2x +2

Group terms and move the constant to the opposite side of the equation

y -2 = -2x² + 2x

Factor the leading coefficient

y -2 = -2(x²-x )

Complete the square. Remember to balance the equation by adding the same constants to each side

y -2 -0.25*2= -2(x²-x+0.25 )

y -2.50= -2(x²-x+0.25 )

Rewrite as perfect squares

y -2.50= -2(x-0.50)²

Part a) The equation of a parabola in vertex form is. y=a(x−h)2+k

so

y -2.50= -2(x-0.50)²> y = -2(x-0.50)²+2.50

the answer Part a) is

y = -2(x-0.50)²+2.50

part b) Find the vertex

we know that the vertex is the point (h,k)

so

(h,k) is the point> (0.50,2.50)

the answer part b) is

the vertex is the point (0.50,2.50)

Part c) find the value for x = 6

y = -2(x-0.50)²+2.50> y = -2(6-0.50)²+2.50> y = -2(5.50)²+2.50

y=-60.50+2.50> y=-58

the answer Part c) is

-58

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752