What are the domain and range of the function f(x)=sqrt(x-7) +9

Domain: x ≥ 7

Range (7,9)

Domain : { x ∈ R : x ≥ 7 }

Range: { f ∈ R : f ≥ 9 }

Step-by-step explanation:

Given function is:

f(x) =

Firstly find the domain of the given function.

Domain is set of all real x's values where given function is defined.

In other words, we exclude all the x's values from all real values where function is undefined.

In case of square root function, inside the square root given expression must be greater or equal to zero.

So,

x - 7 ≥ 0

Solve for x

x ≥ 7

So, domain is all real x when x ≥ 7.

Now find the Range of this function.

Range is set of all output values.

So, lowest value of out put is 9 when x is 7

and maximum value of the function is infinite.

So,

Range is all real f's values when f ≥ 9.

add an image

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet