Eab and dcb are two right triangles. the figure has bed≅ bde. point b is the midpoint of segment ac. prove: eab≅ dcb

we know both triangles are right-triangles, so they must have a 90° angle somewheres.

we also know that B is the midpoint of AC, so the segments of AB = BC, so we know the triangles have that side in common length.

but we also know that the ∡BED = ∡BDE, so the triangles have that angle in common as well.

well, the angles made at the vertex B, namely ∡ABE and ∡CBD, can't be 90°, due to the inclination from the sides E and D, so the right-angles must be at vertices A and D.

∡BAE = ∡BCDANGLE

∡BED = ∡BDEANGLE

AC = BCSIDE

so the triangles are congruent by AAS.

1. 34

2. 268

3. x=14.4

step-by-step explanation:

step-by-step explanation:

at each of the parallel lines adjacent angles are supplementary. the angles have special names identifying their positions with respect to the parallel lines and transversal. they are corresponding angles, alternate interior angles, or alternate exterior angles. an angles is congruent to its matched angle.