There are 43 cars that start in every nascar sprint cup race. how many ways can they place in the top 5 at each race? 2. there are 102 students in john's freshman seminar class at suny oneonta. the professor tells her students she will be assigning a project in which the students will work in pairs and that she will be selecting the pairs of students. how many pairs of students are possible?

1. Assuming we're not concerned with the order of finish, the number is the number of ways 5 can be chosen from 43.

... C(43, 5) = 43!/(5!·(43-5)!) = (43·42·41·40·39)/(5·4·3·2·1) = 962,598

2. There are 102 choose 2 = C(102, 2) = 102*101/(2*1) = 5,151 ways to pair one student with another.

There are more than 2.75×10⁸⁰ ways the class of 102 can be divided into pairs of students. That number is 102!/(51!·2⁵¹).

it could be a ..idk tho

x=half

step-by-step explanation: