Me fast find the mean of 10, 44, 54, 55, 65, 65, 66 with the 1. mean with outlier 2. mean without outlier find the median of 10, 44, 54, 55, 65, 65, 66 with the 1. median with outlier 2. median without outlier

In this particular instance, the outlier is the number radically different from the other numbers. For this it would be 10.

The mean or average for the first set of numbers is 359 / 7, so 59.28 with the outlier. Without the outlier it would be 58.166 repeating.

The median of this set of numbers is 55 with the outlier, and 60 without the outlier.

If you mix up mode, median, and mean, I learned it as

Mode mode mode's the most

Average is the mean

Median Median median median always in between

Hope I helped.

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: