What are the values of a, b, and c in the quadratic formula given the equation 3x^2-x= 4? a. a=3, b=0, c=-4b. a=3, b=1, c=4c. a=3, b=1, c=4d. a=3, b=-1, c=-42. what is the first correct step for solving the equation, x^2+x=12 ?

First question:

First of all, you have to rewrite the quadratic equation bringing everything to the left hand side, so you have

Now, the coefficients of a quadratic equation are usually read as , i.e. is the coefficient of , is the coefficient of and is the constant term.

Once you rewrite your equation, the coefficient of is 3, the coefficient of is and the constant term is , so the correct answer is D.

Second question:

As discussed above, the first step for solving a quadratic equation is bringing everything to the left, so that you are in the form . So, the first thing you have to do is to transform

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.