Which octant contains the image of point a( 1, -3, 4) after a reflection about the xz - plane?

Hi,

Concept: The given problem is based on 3 Dimensional Geometry.

Consider three axes in defined space be x, y & z in their positive directions then - x , -y & -z be their negative axes.

The coordinate of given point A(x1, y1, z1) = (1, -3, 4)

If we take the reflection of point A about xz - plane x and z coordinates will remain same and y-coordinate will give its reflection. It means the value of y-coordinate will be changed which will be +ve 3.

Hence, the reflection of A(1, -3, 4) will be A'(x2, y2,z2= (1, 3, 4).

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )