The sum of three consecutive integers is three more than twice the middle integer. create an equation and solve to find the integers. can someone me out? and explain and show work!

Let's assume the three consecutive integers are x, x+1 and x+2.

So, sum of x, x+1 and x+2 can be written as x+x+1+x+2.

Twice the middle integer (x+1) will be 2*(x + 1).

Hence 3 more than 2(x+1) can be represent as 3 + 2(x+1).

Hence, we can set u the following equation as following:

x + x + 1 + x + 2 = 3 + 2(x + 1).

3x + 3 = 3 + 2x + 2

3x + 3 = 2x + 5 Combine the like terms.

3x + 3- 3 = 2x + 5 - 3 Subtract 3 from each sides.

3x = 2x + 2

3x - 2x = 2x + 2 - 2x Subtract 2x from each sides.

x = 2

So, the first integer is 2.

Second integer is 2+ 1 = 3 and

Third integer 2+2 = 4

So, the three consecutive integers are 2, 3 and 4.

"Hope this helps!!"

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: