Abag contains one red pen, four black pens, and three blue pens. two pens are randomly chosen from the bag and are not replaced. to the nearest hundredth, what is the probability that a black pen is chosen first and then another black pen is chosen? 0.020.190.210.25

one+four+three=eight pens.

Two pens are selected without replacement.

Need probability of selecting two black pens.

Probability of selecting first black pen is four out of eight, 4/8

Probability of selecting second black pen is three remaining black pens out of the remaining 7 pens = 3/7

Probability of both events happening is the product of the two probabilities, according to the multiplication rule.

Therefore probability of selecting two black pens out of the initial eight pens

=(4/8)(3/7)=3/14=0.2143 (to the ten-thousandth).

Rounding to the hundredth will give you the required answer.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225