Which of the following represents the area of a rectangle whose length is x + 1 and whose width is x + 11? a.) x2+ 11 b.) x2+ 12x + 11 c.) x2+ 11x + 12 d.) x2+ 10x + 11

Area is length * Width.

So the area of this rectangle would be

(x+1)(x+11)

This is a binomial so we can FOIL the two equations to get our answer

First

Outer

Inner

Last

For the F we multiply the first two terms in each expression together

(x+1)(x+11) x * x= x^2

For the O we multiply the two outer terms together

(x+1)(x+11) x*11= 11x

So far we have x^2 + 11x

For the I, we multiply the two inner terms together

(x+1)(x+11) 1*x= 1x or x

now we have x^2 + 11x +x

For the L, we multiply the last terms of both monomials together.

(x+1)(x+11) 1 * 11= 11

The area is x^2 +11x +x + 11

B. x^2 + 12x + 11 is your answer

step-by-step explanation:

the answer is (-4,-4)

hope this ! : d