Using a spectrometer, a sample was analyzed to have a percent transmittance of 85%. what percentage of light was actually absorbed by the sample?

Using a spectrometer, a sample was analyzed to have a percent transmittance of 85%. This means that the remainder of the light was absorbed by the sample given in the question.

Now, from the 100% light that has been incident on the sample, if 85% was transmitted, then the percentage of light was actually absorbed by the sample can be found out as:

percentage of light was actually absorbed by the sample=100% - (percentage of light transmitted by the sample)

Therefore, percentage of light was actually absorbed by the sample=100%-85%=15%

Thus, 15% light was actually absorbed by the sample.

0

step-by-step explanation:

you can not divide by 0 so 4 ÷ 0 would be 0

0 × 9999 =0

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