What are the coordinates of the hole in the graph of the function f (x) f (x) = x^2 - 9 / x - 3 _ , _

The hole in this function exists at (3, 0).

To find a hole, you must find what first makes the bottom of the equation (the denominator) equal to 0.

x - 3 = 0

x = 3

Now knowing this, we plug 3 in to the top of the equation, to find the y value that will not be possible either.

x^2 - 9

3^3 - 9

9 - 9

0

i hope this is what you were looking for.

see attached graph