Jacob is solving the equation 3√3q = 27 for q. his work is shown. 3√3q = 27 √3q = 9 (√3q)^ = 9^ 3q = a q = b what are the correct values for a and b? (^ stands for squared)

The given problem is stated as below:

3√3q = 27

√3q = 9

(√3q)^ = 9^

(^ stands for squared )

3q = A

Therefore we have,

A = 9^

or, A = 81

Again it is given that,

3q = A

or, 3q = 81.

or, q = 81/3 = 27

q = 27

As per the problem q = B,

therefore we can conclude that B = 27

So by solving the problem we get the final answer as below:

A = 81 and B =27

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)

i will with my problems and all the other things that need to   be on by the way

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