Astadium has central rectangular area 125m long by 80 m wide there are two semicircular ends. running tracks goes all way round

) Using formula for cicumference.

Circumference = Pi * diameter

Circumference = Pi * 80m

Circumference = 251.2m.

Total inside length of the curved ends.

2)Total distance round inside of track =

2(125) + 251.2m

= 250 + 251.2

= 501.2m

3) Area of circular ends =

Pi*r^2

= Pi*40^2

= 5024m^2

Area of central area (rectangle)

length * width

125m * 80m

= 10,000m^2

Total area inside track =

5,024m^2 + 10,000m^2

= 15,024m^2

Hope this helps.

:-)

answer: 4 (:

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)