What is the biggest whole number smaller than the perimeter of any triangle with a side of length 5.6 and a side of length 19.7?

Concept: (i) Perimeter of a triangle: The sum of all three sides of the triangle is called its perimeter.

(ii) Fact: The sum of any two sides of a triangle is always greater than its third side.

Given: First side of triangle = 5.6 unit.

Second side of triangle = 19.7 unit.

Let third side of the triangle be 's' unit.

The perimeter of triangle = (5.6 +19.7 + s) unit.

But as per the fact given above, s < (5.6 +19.7)

or, s < 25.3 (i)

Now, we shall add 25.3 both the sides in equation (i) to make the left hand side equal to the perimeter.

So, the perimeter of triangle = s + 25.3 < 25.3 + 25.3 = 50.6

Now, to make 50.6 as next whole number smaller than the perimeter which will be 50.

Hence, 50 is the biggest whole number smaller than the perimeter of the triangle with a side of length 5.6 unit and a side of length 19.7 unit.

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116