Ahorse corral is situated on a triangular plot of land. two sides of the plot are 150 feet long and they meet at an angle of 55°. a fence is to be placed along the perimeter of the corral. how much fencing material is needed? a. 125 ft b. 138.5 ft c. 288.5 ft d. 438.5 ft

Answer : d. 438.5 ft

The diagram for the given statement is attached below.

Two sides AB and AC are equal so the angle B = angle C

WE know sum of three sides of a triangle = 180

angle A + angle B + angle C = 180

55 + B + C = 180

B + C = 180 -55 = 125

B and C are equal so we divide 125 by 2

angle B = 62.5 and angle C = 62.5

Now we apply sin law

150 * sin(55) = sin(62.5) * a

122.8728066 = sin(62.5) * a

a =

a= 138.52 feet

To find perimeter we add all the sides

150 + 150 + 138.52 = 438.52 feet

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