He access code for a car's security system consists of four digits. the first digit cannot be 8 and the last digit must be even . how many different codes are available? the number of different codes available is nothing .

There are 10 total numbers ( 0, 1, 2,3, 4, 5, 6, 7, 8, 9)

The first number cannot be an 8, so it can be 9 different numbers.

The second number can be any of 10 numbers.

The third number can also be any of 10 numbers.

The fourth number can only be even so it can be 0, 2 , 4, 6, 8, so any of 5 numbers.

To find the total combinations, multiply the available choices by each other:

9 x 10 x 10 x 5 = 4,500 different combinations.

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )