Ireally need with this question! : explain step by step! you. " in a scale drawing of a triangular banner, one side measure's 16 centimeters and the other two sides each measure 12 centimeters. on the actual banner, these two sides each measure 36 feet. what is the lenght of the remaining side of the actual banner? "

The three sides have the ratios

... (16 cm) : (12 cm) : (12 cm)

and

... (x ft) : (36 ft) : (36 ft)

Perhaps you can see that the numbers in the second ratio are 3 times the numbers in the first ratio, with cm changed to ft. If we multiply 16 cm by 3 and change cm to ft, we get

... x ft = (16 cm)*(3 ft/cm) = 48 ft

The length of the remaining side is 48 ft.

we know the sides on the isosceles triangle are 12, 12 and 16 on the drawing on paper.

we also know that the actual size for the 12-twin sides is 36, so we can set a proportion using those two and check at what ratio the drawing : actual are.

since we know the drawing : actual ratio is really 1 : 3, then we can use that to find the actual size for the last side, we know on the drawing is 16 cm, so

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.