Arnold is playing a game where he is trying to roll a two with a standard die. if he gets a two in any of his first 6 rolls, he wins; otherwise he loses. what is the probability that arnold wins the game? round your answer to the nearest tenth of a percent. a. 42.1% b. 51.8% c. 66.5% d. 59.8%

 C.66.5%

Step-by-step explanation:

Given: Arnold is playing a game where he is trying to roll a two with a standard die.

We know that for any event P(A) = 1 - P(A')  

Therefore, P(win)=1-P(lose)

Thus, he loses if he never rolls a 2 in the 6 rolls.  

The total number of outcomes = 6

There number of losing outcomes (1, 3, 4, 5, 6)=5

Therefore, the probability that Arnold loses the game is given by :-

Now, the probability that Arnold wins the game is given by :-

In percent, the probability that Arnold wins the game is given by :-

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step-by-step explanation:

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