Find the equation of the line with a y-intercept of -3 and a x-intercept of -4.5

So with intercepts, we know that one of the coordinates is 0 - that is because the line intercepts the axis at this point.

When we have a y-intercept of -3, it is written as (0,-3)

And when we have an x-intercept of -4.5, we write it as (-4.5,0)

So now we have our two points - let's find the slope using the equation:

--->

If we convert -4.5 to an improper fraction, we get:

So then we go back and simplify:

So now we have our slope: . Then we can write the equation:

Let's use the point (0,-3) to solve for b:

So now we can write the equation:

This is the equation of the line with points (0,-3) and (-4.5,0).

6.5

step-by-step explanation:

you said it was in the question

~courtney

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.