Is it possible to draw parallelogram so that all sides are equal to one of its diagonals? if it is, what would the angles of the parallelogram be?

yes it is.

diagonals of parallelogram bisect each other so if the diagonals are of equal length then they bisect each other and length of each bisect is equal. so the angle made by these bisects with any sides should be equal ( it is a theorem of geometry ) if all such angles are equal then the length all the sides with which these angles are made should of equal.now if all the sides has same length then it is rhombus and here all angles have same values that is x+x+x+x=360; x=90

so it is proved that it is a rectangle.

just needed some points but try socratic

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.