Acoordless phone costs $55 plus $25 for each extra handset. what is the cost of a coordless phone and 3 extra handsets

Given, the cost of a chordless phone = $55

Cost for each handset = $25

Now to find cost for 3 handsets, we have to multiply cost for each handset with number of handsets.

So, the cost for 3 handsets = $(25×3) = $75

We have to find the total cost of a chordless phone and 3 extra handsets.

To find the total cost we have to add the cost of a chordless phone and cost of 3 handsets.

Therefore, the total cost = $55 + $75 = $(55+75) = $130

We have got the required answer.

The total cost is $130.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)