Icant figure this one ! what is the equation of a line passing through the point (6, 1) and parallel to the line whose equation is 3x = 2y + 4? y = -(⅔)x + 5 y = (3/2)x - 8 y = -(⅔)x - 3 y = (3/2)x - 5

3x = 2y + 4

3x + 4 = 2y

y = (3x + 4)/2

y = 3x/2 + 2

Two lines are parallel when their linear coeficient are equal, so,

(y - yo) = m.(x - xo)

m needs to be 3/2

(y - yo) = 3/2 . (x - xo)

(y - 1) = 3/2 . (x - 6)

y - 1 = 3x/2 - 3.6/2

y - 1 = 3x/2 - 9

y = 3x/2 - 9 + 1

y = 3x/2 - 8

      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3

answer: 60%

explanation:

÷

= 60%