What is the next step to solving the following equation by using the quadratic formula? 2n2 - 7n - 3 = 0 n=7±(-7)2-4()2(2)

2n² - 7n - 3 = 0

Δ = b² - 4.a.c

Δ = -7² - 4 . 2 . -3

Δ = 49 - 4. 2 . -3

Δ = 73

There are 2 real roots.

n = (-b +- √Δ)/2a

n' = (--7 + √73)/2.2

n'' = (--7 - √73)/2.2

n' = (7 + √73)/4

n'' = (7 - √73)/4

answer: i'm not sure

step-by-step explanation:

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