Given: f(x)=x^4-8x^2+5 find all roots to the nearest 0.001

We let x square =y

so x to the power 4 = y square

and we get

To find the zroes, we need to set f(y) to 0 and solve for y .

Now we use completing the square method

Now we do the back substitution.

and

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15