How can 1/4x-3=1/2x+8 be set up as a system of equations? ? a) 4y+4x=-12 2y+2x=16 b) 4y-x=-12 2y-x=16 c) 4y+x=-12 2y+x=16 d) 4y-4x=-12 2y-2x=16

we are given

Let's assume it is equal to y

so, we can write

we can multiply both sides by 4

so, we got

first equation is

now, we can find second equation

we can multiply both sides by 2

so, we got

system of equations as

[tex] 4y-x=-12 [/tex

so, option-B..............Answer

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: