Abag has 2 green marbles, 3 red marbles, and 3 yellow marbles. what is the probability that you pick a green marble, do not replace it, and pick a yellow marble? a bag has 2 green marbles, 3 red marbles, and 3 yellow marbles. what is the probability that you pick a green marble, do not replace it, and pick a red marble?

Sorry, I did them out of order because I started doing the second problem first on accident.

For the second question: the probability that you choose a green marble is 2/(2 + 3 + 3) = 2/8 = 1/4. The probability that you choose a red marble without replacing the green one is: 3/(2 + 3 + 3 - 1) = 3/7. Now, multiply these two fractions together because they depend on each other:

1/4 * 3/7 = 3/28

For the first question: the probability you choose a green marble is still 1/4. The probability that you choose a yellow marble is 3/(2 + 3 + 3 - 1) = 3/7. Multiply these two fractions together and you get: 1/4 * 3/7 = 3/28 again.

The answer to both questions is 3/28.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

answer: 10 meter

step-by-step explanation:

need details