Solve x + y + z = -6 -2x – 2y – 2z = 12 5x + 5y + 5z = -30 solve x + y = 6 y + z = 0 x + y – z = 4

here we have given three system of linear equations.

x+y+z=-6

-2x-2y-2z=12

5x+5y+5x=-30.

here three unknowns will have same value x=y=z .

the x+y+z=-6

x+x+x=-6=3x=-6,x=-2

we know that x=y=z .

then x=-2 y=-2 and z=-2.

for part b we have three equation x+y=6

y+z=0

x+y-z=0

we need to use substitution method.

in second equation we have y+z=0 it mean y=-z

we need to plug y=-z in any one of the equation to find other value.

in first equation we have x+y=6 it becomes x-z=6

then in third equation we have x+y-z=4 we will rewrite this as x-z+y=4

we know that x-z=6

so 6+y=4

y=-2

y+z=0 =-2+z=0

z=2

we know x+y=6

x+(-2)=6=x=8.

x=8 y=-2 z=2

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?