The sum of three numbers is 13. the sum of twice the first number, 4 times the second number, and 5 times the third number is 40. the difference between 5 times the first number and the second number is 39. find the three numbers.

The first number is 8, the second number is 1 and the third number is 4.

To find all of these, we first need to write a system of equations bsaed on the sentences. For this purpose, we'll use x as the first number, y as the seocnd number, and z as the third number.

x + y + z = 13

2x + 4y + 5z = 40

5x - y = 39

To start solving this, we need to combine the first two equations to get the z term to cancel. Multiply the first equation by -5 and add together.

-5x - 5y - 5z = -65

2x + 4y + 5z = 40

-3x - y = -25

Now we can combine the new equation along with our 3rd equation to cancel out y and solve for x. Multiply the new equation by -1.

3x + y = 25

5x - y = 39

8x = 64

x = 8

Now that we have the value of x, we can solve for y using the 3rd equation.

5x - y = 39

5(8) - y = 39

40 - y = 39

-y = -1

y = 1

Now we can find z using the values we got and the first equation.

x + y + z = 13

8 + 1 + z = 13

9 + z = 13

z = 4

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a

idk wbu

step-by-step explanation: