What are the amplitude, period, phase shift, and midline of f(x) = −4 cos(3x − π) + 1? amplitude: −4; period: pi over 3; phase shift: x = pi over 4; midline: y = −1 amplitude: 4; period: pi over 3; phase shift: x = pi over 4; midline: y = 1 amplitude: −4; period: 2 pi over 3; phase shift: x = pi over 3; midline: y = −1 amplitude: 4; period: 2 pi over 3; phase shift: x = pi over 3; midline: y = 1?

Alright, lets get started.

The standard form for cos function is

Where

A = Amplitude (positive value)

Period =

Phase shift =

Mid line or vertical shift = D

So, comparing the given function with standard

A = 4

B = 3

C=

D = 1

Means Amplitude = 4

Period =

Phase shift =

Mid line = 1

Hence the answer is last choice 4.

Hope it will help :)

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076